<font><font face="verdana,sans-serif">well, approximately like this:</font></font><div><ul><li><span style="font-family:verdana,sans-serif">clear image (set all pixels to zero)</span></li><li><span style="font-family:verdana,sans-serif">for x=0 to image.size(0)</span></li>
<li><span style="font-family:verdana,sans-serif">y=m*x+c</span></li><li><span style="font-family:verdana,sans-serif">if y>=</span><span style="font-family:verdana,sans-serif">image.size(0) OR y<0 continue;</span></li>
<li><span style="font-family:verdana,sans-serif">else image.setpixel(x,y,1)</span></li><li><span style="font-family:verdana,sans-serif">next x</span></li></ul><font face="verdana, sans-serif">For parabola, you need to explicitly solve it for y to use above approach, or solve for x and iterate over y and calculate x.</font></div>
<div><font face="verdana, sans-serif">This approach doesn't do anti-aliasing, of course. If you need anti-aliasing, you can use <a href="http://en.wikipedia.org/wiki/Xiaolin_Wu%27s_line_algorithm">Xiaolin Wu's algorithm</a>.<br>
</font><br><div class="gmail_quote">On Fri, Oct 12, 2012 at 10:57 AM, Raviteja, Allaparthi <span dir="ltr"><<a href="mailto:Allaparthi.Raviteja@philips.com" target="_blank">Allaparthi.Raviteja@philips.com</a>></span> wrote:<br>
<blockquote class="gmail_quote" style="margin:0 0 0 .8ex;border-left:1px #ccc solid;padding-left:1ex">
<div lang="EN-US" link="blue" vlink="purple">
<div>
<p class="MsoNormal">Hi,</p>
<p class="MsoNormal"> </p>
<p class="MsoNormal">I have been stuck with the problem of drawing a parabola of the form ((y-k)*(y-k))=4a(x-h) and drawing a line of the form y=mx+c into an image in ITK .Could someone please help me out .</p>
<p class="MsoNormal"> </p>
<p class="MsoNormal">Regards,</p>
<p class="MsoNormal">Ravi Teja.</p>
<p class="MsoNormal"> </p>
<p class="MsoNormal"> </p>
<p class="MsoNormal"> </p>
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