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The problem with the approach in the paper is that RT structure contours can have arbitrary resolution.<BR><BR>Xiaofeng<BR><BR><BR><BR> <BR>
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From: Jason.Dowling@csiro.au<BR>To: xf10036@hotmail.com<BR>CC: insight-users@itk.org<BR>Date: Wed, 5 May 2010 10:06:03 +1000<BR>Subject: Re: Creating an approximate cross-section of a RT<BR><BR>
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<P class=ecxMsoNormal><FONT face=Arial size=2><SPAN style="FONT-SIZE: 10pt; FONT-FAMILY: Arial">Hi </SPAN></FONT><FONT face="Courier New" size=2><SPAN style="FONT-SIZE: 10pt; FONT-FAMILY: 'Courier New'">Xiaofeng, </SPAN></FONT></P>
<P class=ecxMsoNormal><FONT face="Courier New" size=2><SPAN style="FONT-SIZE: 10pt; FONT-FAMILY: 'Courier New'"> </SPAN></FONT></P>
<P class=ecxMsoNormal><FONT face="Courier New" size=2><SPAN style="FONT-SIZE: 10pt; FONT-FAMILY: 'Courier New'">You can use the code from this Insight Journal paper: <A href="http://www.insight-journal.org/browse/publication/701">http://www.insight-journal.org/browse/publication/701</A> to read the DICOM-RT structures into a binary volume. An easy way to then visualize the different orientations of the ROI is to load it into ITK-SNAP ( <A href="http://www.itksnap.org/pmwiki/pmwiki.php">http://www.itksnap.org/pmwiki/pmwiki.php</A> ). </SPAN></FONT></P>
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<P class=ecxMsoNormal><FONT face="Courier New" size=2><SPAN style="FONT-SIZE: 10pt; FONT-FAMILY: 'Courier New'">Cheers,</SPAN></FONT></P>
<P class=ecxMsoNormal><FONT face="Courier New" size=2><SPAN style="FONT-SIZE: 10pt; FONT-FAMILY: 'Courier New'">Jason</SPAN></FONT></P>
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<P class=ecxMsoNormal><FONT face="Times New Roman" size=3><SPAN style="FONT-SIZE: 12pt">-----</SPAN></FONT></P>
<P class=ecxMsoNormal><FONT face="Courier New" size=2><SPAN style="FONT-SIZE: 10pt; FONT-FAMILY: 'Courier New'"> </SPAN></FONT></P></DIV>
<P class=ecxMsoNormal><FONT face="Courier New" size=2><SPAN style="FONT-SIZE: 10pt; FONT-FAMILY: 'Courier New'">All,</SPAN></FONT></P>
<P class=ecxMsoNormal><FONT face="Courier New" size=2><SPAN style="FONT-SIZE: 10pt; FONT-FAMILY: 'Courier New'"> </SPAN></FONT></P>
<P class=ecxMsoNormal><FONT face="Courier New" size=2><SPAN style="FONT-SIZE: 10pt; FONT-FAMILY: 'Courier New'"> </SPAN></FONT></P>
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<P class=ecxMsoNormal><FONT face="Courier New" size=2><SPAN style="FONT-SIZE: 10pt; FONT-FAMILY: 'Courier New'">I've post this in VTK board but I didn't get the answer. Before I set</SPAN></FONT></P>
<P class=ecxMsoNormal><FONT face="Courier New" size=2><SPAN style="FONT-SIZE: 10pt; FONT-FAMILY: 'Courier New'"> </SPAN></FONT></P>
<P class=ecxMsoNormal><FONT face="Courier New" size=2><SPAN style="FONT-SIZE: 10pt; FONT-FAMILY: 'Courier New'">out to implement it, I'll post it here.</SPAN></FONT></P>
<P class=ecxMsoNormal><FONT face="Courier New" size=2><SPAN style="FONT-SIZE: 10pt; FONT-FAMILY: 'Courier New'"> </SPAN></FONT></P>
<P class=ecxMsoNormal><FONT face="Courier New" size=2><SPAN style="FONT-SIZE: 10pt; FONT-FAMILY: 'Courier New'"> </SPAN></FONT></P>
<P class=ecxMsoNormal><FONT face="Courier New" size=2><SPAN style="FONT-SIZE: 10pt; FONT-FAMILY: 'Courier New'"> </SPAN></FONT></P>
<P class=ecxMsoNormal><FONT face="Courier New" size=2><SPAN style="FONT-SIZE: 10pt; FONT-FAMILY: 'Courier New'">I have a set of contours in axial orientation representing a ROI. I</SPAN></FONT></P>
<P class=ecxMsoNormal><FONT face="Courier New" size=2><SPAN style="FONT-SIZE: 10pt; FONT-FAMILY: 'Courier New'">need to sketch the ROI in coronal and sagittal plane, by connection the</SPAN></FONT></P>
<P class=ecxMsoNormal><FONT face="Courier New" size=2><SPAN style="FONT-SIZE: 10pt; FONT-FAMILY: 'Courier New'">points made from the intersection of the contours and the cutting plane.</SPAN></FONT></P>
<P class=ecxMsoNormal><FONT face="Courier New" size=2><SPAN style="FONT-SIZE: 10pt; FONT-FAMILY: 'Courier New'">Is there a function to do that in vtk or in ITK?</SPAN></FONT></P>
<P class=ecxMsoNormal><FONT face="Courier New" size=2><SPAN style="FONT-SIZE: 10pt; FONT-FAMILY: 'Courier New'"> </SPAN></FONT></P>
<P class=ecxMsoNormal><FONT face="Courier New" size=2><SPAN style="FONT-SIZE: 10pt; FONT-FAMILY: 'Courier New'"> </SPAN></FONT></P>
<P class=ecxMsoNormal><FONT face="Courier New" size=2><SPAN style="FONT-SIZE: 10pt; FONT-FAMILY: 'Courier New'"> </SPAN></FONT></P>
<P class=ecxMsoNormal><FONT face="Courier New" size=2><SPAN style="FONT-SIZE: 10pt; FONT-FAMILY: 'Courier New'">Some in VTK board suggested constructing a surface and create</SPAN></FONT></P>
<P class=ecxMsoNormal><FONT face="Courier New" size=2><SPAN style="FONT-SIZE: 10pt; FONT-FAMILY: 'Courier New'"> </SPAN></FONT></P>
<P class=ecxMsoNormal><FONT face="Courier New" size=2><SPAN style="FONT-SIZE: 10pt; FONT-FAMILY: 'Courier New'">the crosssection by cutting the surface. But that is not what I need.</SPAN></FONT></P>
<P class=ecxMsoNormal><FONT face="Courier New" size=2><SPAN style="FONT-SIZE: 10pt; FONT-FAMILY: 'Courier New'"> </SPAN></FONT></P>
<P class=ecxMsoNormal><FONT face="Courier New" size=2><SPAN style="FONT-SIZE: 10pt; FONT-FAMILY: 'Courier New'">I need to do it in the rudimentary way for performance.</SPAN></FONT></P>
<P class=ecxMsoNormal><FONT face="Courier New" size=2><SPAN style="FONT-SIZE: 10pt; FONT-FAMILY: 'Courier New'"> </SPAN></FONT></P>
<P class=ecxMsoNormal><FONT face="Courier New" size=2><SPAN style="FONT-SIZE: 10pt; FONT-FAMILY: 'Courier New'"> Many thanks!</SPAN></FONT></P>
<P class=ecxMsoNormal><FONT face="Courier New" size=2><SPAN style="FONT-SIZE: 10pt; FONT-FAMILY: 'Courier New'"> </SPAN></FONT></P>
<P class=ecxMsoNormal><FONT face="Courier New" size=2><SPAN style="FONT-SIZE: 10pt; FONT-FAMILY: 'Courier New'">Xiaofeng</SPAN></FONT></P>
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